16t^2+96t+144=0

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Solution for 16t^2+96t+144=0 equation: 



16t^2+96t+144=0

a = 16; b = 96; c = +144;
Δ = b2-4ac
Δ = 962-4·16·144
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{-96}{32}=-3$

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